{{{id=1| b=RR(3.0, 1000) places=6 left = [[N(-10^-k,digits=places),N((b^(-(10^-k)) - 1)/(-(10^-k)), digits=places)] for k in range(1,places+1,1)] right = [[N(10^-k,digits=places),N((b^(10^-k) - 1)/(10^-k), digits=places)] for k in range(places,0,-1)] html.table([['$h$','$(b^h-1)/h$']] + left + [[0,'undefined']] + right) ///
undefined | |